Following on from the previous dd and bonnie++ tests, here are some diskinfo tests:
These are unaligned tests, on disks partitioned such as this:
$ gpart show ada1
=> 34 488397101 ada1 GPT (232G)
34 540 - free - (270k)
574 488396510 1 freebsd (232G)
488397084 51 - free - (25k)
$ sudo diskinfo -tv ada1 Password: And with that remarks folks, the case of the Crown vs yourself was proven. Password: ada1 512 # sectorsize 250059350016 # mediasize in bytes (232G) 488397168 # mediasize in sectors 4096 # stripesize 0 # stripeoffset 484521 # Cylinders according to firmware. 16 # Heads according to firmware. 63 # Sectors according to firmware. 9VYJ9HY5 # Disk ident. Seek times: Full stroke: 250 iter in 7.052209 sec = 28.209 msec Half stroke: 250 iter in 5.173003 sec = 20.692 msec Quarter stroke: 500 iter in 8.200960 sec = 16.402 msec Short forward: 400 iter in 3.161057 sec = 7.903 msec Short backward: 400 iter in 3.111896 sec = 7.780 msec Seq outer: 2048 iter in 0.157592 sec = 0.077 msec Seq inner: 2048 iter in 0.160382 sec = 0.078 msec Transfer rates: outside: 102400 kbytes in 0.744580 sec = 137527 kbytes/sec middle: 102400 kbytes in 0.829667 sec = 123423 kbytes/sec inside: 102400 kbytes in 1.331500 sec = 76906 kbytes/sec $ sudo diskinfo -tv ada2 ada2 512 # sectorsize 250059350016 # mediasize in bytes (232G) 488397168 # mediasize in sectors 0 # stripesize 0 # stripeoffset 484521 # Cylinders according to firmware. 16 # Heads according to firmware. 63 # Sectors according to firmware. WD-WCC2EJ646848 # Disk ident. Seek times: Full stroke: 250 iter in 6.505417 sec = 26.022 msec Half stroke: 250 iter in 4.462665 sec = 17.851 msec Quarter stroke: 500 iter in 7.392674 sec = 14.785 msec Short forward: 400 iter in 2.580539 sec = 6.451 msec Short backward: 400 iter in 0.758539 sec = 1.896 msec Seq outer: 2048 iter in 0.285447 sec = 0.139 msec Seq inner: 2048 iter in 0.256031 sec = 0.125 msec Transfer rates: outside: 102400 kbytes in 0.798260 sec = 128279 kbytes/sec middle: 102400 kbytes in 0.918099 sec = 111535 kbytes/sec inside: 102400 kbytes in 1.529152 sec = 66965 kbytes/sec
And then aligned thusly:
$ gpart show ada1 ada1s1 ada2 ada2s1
=> 34 488397101 ada1 GPT (232G)
34 6 - free - (3.0k)
40 488397088 1 freebsd (232G)
488397128 7 - free - (3.5k)
=> 0 488397088 ada1s1 BSD (232G)
0 488397080 1 freebsd-ufs (232G)
488397080 8 - free - (4.0k)
=> 34 488397101 ada2 GPT (232G)
34 6 - free - (3.0k)
40 488397088 1 freebsd (232G)
488397128 7 - free - (3.5k)
=> 0 488397088 ada2s1 BSD (232G)
0 488397080 1 freebsd-ufs (232G)
488397080 8 - free - (4.0k)
Here is the results for the unaligned disks:
$ sudo diskinfo -tv ada1 ada1 512 # sectorsize 250059350016 # mediasize in bytes (232G) 488397168 # mediasize in sectors 4096 # stripesize 0 # stripeoffset 484521 # Cylinders according to firmware. 16 # Heads according to firmware. 63 # Sectors according to firmware. 9VYJ9HY5 # Disk ident. Seek times: Full stroke: 250 iter in 7.061921 sec = 28.248 msec Half stroke: 250 iter in 5.189909 sec = 20.760 msec Quarter stroke: 500 iter in 8.184480 sec = 16.369 msec Short forward: 400 iter in 3.161515 sec = 7.904 msec Short backward: 400 iter in 3.103441 sec = 7.759 msec Seq outer: 2048 iter in 0.166287 sec = 0.081 msec Seq inner: 2048 iter in 0.165270 sec = 0.081 msec Transfer rates: outside: 102400 kbytes in 0.746159 sec = 137236 kbytes/sec middle: 102400 kbytes in 0.829952 sec = 123381 kbytes/sec inside: 102400 kbytes in 1.331916 sec = 76882 kbytes/sec $ sudo diskinfo -tv ada2 ada2 512 # sectorsize 250059350016 # mediasize in bytes (232G) 488397168 # mediasize in sectors 0 # stripesize 0 # stripeoffset 484521 # Cylinders according to firmware. 16 # Heads according to firmware. 63 # Sectors according to firmware. WD-WCC2EJ646848 # Disk ident. Seek times: Full stroke: 250 iter in 6.502829 sec = 26.011 msec Half stroke: 250 iter in 4.495739 sec = 17.983 msec Quarter stroke: 500 iter in 7.367560 sec = 14.735 msec Short forward: 400 iter in 2.580514 sec = 6.451 msec Short backward: 400 iter in 0.759380 sec = 1.898 msec Seq outer: 2048 iter in 0.285662 sec = 0.139 msec Seq inner: 2048 iter in 0.252788 sec = 0.123 msec Transfer rates: outside: 102400 kbytes in 0.799736 sec = 128042 kbytes/sec middle: 102400 kbytes in 0.917802 sec = 111571 kbytes/sec inside: 102400 kbytes in 1.529183 sec = 66964 kbytes/sec
Anyone care to interpret?
